Yup, that's it - 50 watts / 12.6 nominal DC voltage = 3.9 amps. I too would throw in a 5, as doubt you could find a 4. Recall fuses are there to protect the wiring from burning ...JMichael said:5 amps (amps = watts / volts) Based on my understanding of electronics, that's nonsense to think the size of the fuse can control the brightness of a light, as long as you haven't blown the fuse that is.
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